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A thin semi-circular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed v, is- (NEET 2014) (a) Zero (b) (frac {{ Bvπr }^{2}}{ 2 }) (c) πrBv and R is at higher potential (d) 2rBv and R is at higher ...

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If its vertical (RBSESolutions) height is 24 cm, find its slant height. Solution : ... [∵ 1 litre = 1000 cm 3] Let the side of conical vessel be = x ∴ Volume of the vessel = x 3 cm 3 ∴ 8000 = x 3 ... The diameter of a roller is 84 cm and its length ¡s 120 cm. If it takes 500 (RBSESolutions) ...

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E.g. 12.56. The number of digits in the decimal part is the number of decimal places. E.g., the number 12.56 has two decimal places. 12. To add or subtract decimal numbers write the numbers one below the other so that the decimal points are in one vertical line. Then add or subtract. 13.

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The region where the ball and the vertical jet of water are in contact is a region of low pressure because of higher velocity. The pressure on the other side of the ball is larger. Due, to the pressure difference, the ball remains suspended. ... m = Vρ = Ahρ (∵ V = Ah) ∴ (P 2 – P 1)A = Ahρg or (P 2 – P 1) = hρg. If the point x lies ...

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instant in its motion Tension T Weight W Solution Ans D ...

Example 15 (uniform, vertical) A stone of mass 0.60 kg, attached to a string of length 0.50 m, is whirled in a vertical circle at a constant speed. If the maximum tension in the string is 30 N, calculate (a) the speed of the stone, (b) the maximum number of …

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Under this condition, the weight of the tethered cable F w,R is balanced with the vertical force F ty,R provided by the bobbin in Fig. 9 as follows: (11a) F w, R = ρ t g l t ≅ ρ t g h cos θ = F t y, R = F t, R cos θ, (11b) F t, R ≥ ρ t g h ∵ cos θ = ρ t g h F t, R ≤ 1 for 0 ≤ θ ≤ π 2, where the curved tethered cable is ...

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from the output you made in learning Task 5 explain how to ...

in order to tenderize meat you need to know makes meat tough. a lot of (1.exercise 2. food 2. rest) make the(1. blood 2. bones 3. muscles)make that part of the animal tough. meat also becomes tough with (1 experience 2. age 3. marination). will give brainiest

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If δpqr ≡ ΔEFD then ∠ E — if δpqr ≅ ≅ δefd,

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Strength of Materials by Khurmi - VSIP.INFO

Initially, the system is unstrained. A weight W placed at A causes a vertical deflection at A of 1 and a vertical deflection at B of 2. When the spring is removed, the weight W at A causes a deflection at A of 3. Find the extension in the spring, when it is replaced and the weight W is transferred to B. SOLUTION. ... ∵ P = σ = Stress A From ...

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The sliding of a hard wedge against a softer metallic substrate is a problem of considerable importance in triboplasticity, because it is a model system for asperity contacts in friction [1,2,3,4,5], in applications like sliding wear [3, 6, 7] and deformation processing [8,9,10].The hard wedge is taken to represent an asperity, tool or die.

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Chebyshev Linkage Wheel – GeoGebra

From a), ON (#2 Upper base) is always vertical. ∵ AB is fixed and horizontal. From a), LM (#2 Lower base) is rotate 0 to 180゜. ∵ CD rotates 180゜. [ In same component, Lower and Upper bases move alternately each other. i.e. When one is rotating, the other is not-rotating.

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STD XII Sci. - Shahjahanpedia

makes an angle θ with the lower vertical line Tθ = +mgcosθ r mv2 x. Tension at midway position where θ = 90° (i.e. along horizontal) TM = r mv2 [∵cos 90° = 0] xi. Total energy at different points at the top, bottom and horizontal, EH = EL = EM = 2 5 mrg xii. Total energy at any point, E = mv mgr(1 cos ) 2 1 2 + − θ 7. Conical ...

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[Solved] A planar elastic structure is subjected to ...

Explanation: ∵ ∑ F x = 0 ⇒ H A = 0. since the horizontal reaction is zero, this will act as a simply supported beam ( curved beam ) ∵ ∑ F y = 0 and by symmetry, R A = R B = 12 × 8 2 = 48 k N. The maximum bending moment for a beam under UDL is given as –. M m a x = ω ℓ 2 8 that occurs at the center.

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The natural frequency of the pendulum is the most important characteristic of a dynamic system. It is a function of the mass and stiffness of the system. Now let us consider a simple portal frame as shown in Figure 1.9(a). There are three degrees of freedom per node: one horizontal translation, one vertical translation and one rotation.

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AISSEE Previous Year Question Papers | ENTRANCEINDIA

45. A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 85 cm and length is 1 m. 46. The shape of a garden is rectangular in the middle and semi-circular ends. Total length of the garden including the semi-circular ends is 20 m and its breadth is 7 m.

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Unicode Input · The Julia Language

Unicode Input. The following table lists Unicode characters that can be entered via tab completion of LaTeX-like abbreviations in the Julia REPL (and in …

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1st PUC Physics Question Bank Chapter 5 Laws of Motion ...

1st PUC Physics Laws of Motion Three Marks Questions and Answers. Question 1. Distinguish between mass and weight. Answer: Mass is the amount of matter contained in a body while weight is the gravitational force acting on a body. Mass of body remains same while weight of body varies from place to place.